## ACFM, SCFM & Baseball dents

This is VERY in depth look at ACFM vs. SCFM and why it matters to airflow measurement from Steven Mazzoni… Thanks Steve!

Imagine your job is to figure out how fast baseballs were traveling before they hit a sheet-rock wall. The only method you have is to measure the depth of the dent left in the wall. Suppose at 60 mph, the ball leaves a ¼” deep dent. At 80 mph, it leaves a ½” dent, and so forth. No problem, all you have to do is measure the dents and you can derive the speed (velocity).

But it’s more complicated than that. You discover some of the balls are a bit lighter than others. Otherwise, they are all identical. What does this mean? The lighter balls leave behind a shallower dent than the heavy ones, even if they were traveling at the exact same velocity before hitting the wall. Obviously, more is needed than just the depth of the dents. The weight of the balls must also be factored in. Suppose you are able to weigh the balls in addition to measuring the depth of the dent they leave. You come up with an equation that factors in the ball’s weight and depth of the dent and solves for its velocity.

Something similar to the baseballs is happening when we measure airflow. To determine the airflow

(cfm, or ft^{3}/min) in a duct, all we need to find out is its average velocity (ft/min) and the duct area (ft^{2}). Measuring the air’s velocity (duct traverse) is the tricky part. A pitot tube & manometer measure the speed of the air flowing in a duct. At a faster speed, or velocity, more force is imparted to the column of water in the manometer. The pressure difference (velocity pressure or VP) is used to determine the air’s velocity, in feet/minute.

However, like the baseballs, air’s density isn’t always the same. Thus, the force it imparts to the column of water when traveling at a given velocity changes if it’s density changes. “Heavy” air will lift a column of water to a higher level (velocity pressure, in inches of water) on a manometer than “light” air will, even though moving at the exact same velocity. Thus, the velocity pressure and the air’s density must be factored in before we can determine it’s velocity.

What factors determine air’s density? Mainly its temperature and the barometric pressure. Warm air is lighter (less dense) than cold air. Air at higher barometric pressures near sea level is denser than air at lower pressures (high altitudes). Air’s moisture content also plays a minor role. Moist air (high humidity) at a given temperature is lighter than dry air at the same temperature.

The flow of air (volumetric) is usually expressed in cfm (ft^{3}/min). To be more specific, actual cfm (ACFM) and standard cfm (SCFM) are used. ACFM & SCFM have been defined as follows:

Air is at “standard conditions” when it’s density is @ 0.075 lb/ft^{3}. We can thus conclude a couple of key points. First, if the airflow measurement is taken at or near standard conditions, the ACFM and the SCFM will have the exact same value. Second, if the reading was taken on air at a significantly different density, ACFM and SCFM will have two different values.

Let’s work through an example duct traverse at a high elevation & temperature to show how to determine ACFM & SCFM. Suppose a 4-point duct traverse has been taken at the following conditions. A pitot tube was used to obtain velocity pressures (VP), but these have not yet been converted to velocity (ft/min). Let’s keep it simple and assume a 1.0 ft^{2} duct.

Elevation: | 4,000 ft |

Barometric pressure: | 25.84”hg |

Duct temperature: | 120 deg f |

Duct area: | 12” x 12” = 1.0 ft^{2} |

Actual air density: | 0.059 lb/ft^{3} |

Standard air density: | 0.075 lb/ft^{3} |

Actual velocity pressure (VP) readings: | 0.020” wc |

0.025” wc | |

0.030” wc | |

0.035” wc |

Now, what do we do with these four velocity pressure readings? We need to convert them to velocity, using one of the equations below. The “4,005” equation is only valid for air at standard density. The “1,096” equation works at any density.

Here is where it gets interesting. Which density should we use to convert the VP readings to velocity, so we can then determine ACFM & SCFM? The *actual* density (0.059 lb/ft^{3}), or *standard* density (0.075 lb/ft^{3})? We’ll explore 2 options.

**Option 1:**Calculate the*actual*average duct velocity using the*actual density*of the air measured.

Then multiply average velocity by the duct area in ft^{2}. The result will be in ACFM.

Calculate ACFM Using Option 1:

0.020” wc = | 638 ft/min |

0.025” wc = | 713 ft/min |

0.030” wc = | 782 ft/min |

0.035” wc = | 844 ft/min |

Avg = | 744 ft/min |

- Determine SCFM for our example using one of these 2 methods:
**Method A:**Determine mass flow rate of the ACFM. From that, determine what volumetric flow at standard conditions would result in the same mass flow. The result will be in SCFM.**Method B:**Multiply the ACFM by the ratio of the actual density to standard density. The result will be in SCFM.- Method A & B both result in @ 585 SCFM.
**Option 2:**Even though we realize the actual density at the traverse was*not*standard, calculate using*standard density*. Multiply by the area in ft^{2}. Then take the result and apply a correction factor to determine ACFM & SCFM. o Calculate velocity & flow using the same VP’s from the non-standard density traverse, but using the standard density 4,005 formula:

0.020” wc = | 566 ft/min |

0.025” wc = | 633 ft/min |

0.030” wc = | 694 ft/min |

0.035” wc = | 749 ft/min |

Avg = | 661 ft/min |

- Is this 661 “cfm” the ACFM? No. Is it the SCFM? No. Obviously, it falls in between the 744 ACFM and 585 SCFM we calculated above. What is it then? It is a value that, when corrected, can get us to the true ACFM & SCFM.
- Determine a unique correction factor for our example as follows. Notice the square root function:
- Now what? Use this correction factor to convert the “uncorrected” 661 cfm to ACFM as follows:
- Next, use the same correction factor to convert the “uncorrected” 661 cfm to SCFM as follows:

- Determine a unique correction factor for our example as follows. Notice the square root function:

**Conclusions: **· Consider the type of instrument you are using to measure the differential pressure coming from a pitot tube. Velocity pressure readings from inclined manometers and simple differential pressure instruments will need the correct math applied. Electronic ones may be able to correct for local density and display the actual velocity.

- Both Option 1 & 2 resulted in the same ACFM & SCFM values.
- In Option 1, we used the
*actual*local density to determine the actual average duct velocity and the ACFM. From the ACFM, we calculated the SCFM based on either the mass flow (Method A) or the ratio of actual density to standard density (Method B). - In Option 2,
*standard*density was used to calculate a “reference cfm”. This reference cfm did not reflect reality, but was used to calculate ACFM & SCFM. A correction factor had to be calculated (square root of the ratio of the two densities) and used to convert the reference cfm to ACFM and SCFM. This method is similar to assuming all the baseballs are the heavy ones and calculating a reference speed based on that incorrect premise. Then the result must be corrected based on the actual weight of the baseball. - To avoid confusion, it seems best to use Option 1 along with Method B when working with air at non-standard conditions. At least then, the calculation gives you the ACFM directly, and SCFM can be calculated easily based on the ratio of the two densities. No other correction factors are needed.

Steven Mazzoni

HVAC/R Instructor

Bryan Orr is a lifelong learner, proud technician and advocate for the HVAC/R Trade